Uniform circular motion: An aircraft performs a maneuver called an "aileron roll." During this maneuver, the plane turns like a screw as it maintains a straight flight path, which sets the wings in circular motion. If it takes it 35 s to complete the circle and the wingspan of the plane is 11 m, what is the acceleration of the wing tip? A) 0.18 m/s² B) 0.99 m/s² C) 5.6 m/s² D) 1.0 m/s²

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Quizplus · Accepted Answer

The acceleration of the wing tip is given by:$$a = \frac{v^2}{r}$$where:* v is the speed of the wing tip* r is the radius of the circleThe speed of the wing tip is given by:$$v = \frac{2\pi r}{T}$$where:* T is the period of the circleThe period of the circle is given as 35 s. The radius of the circle is half of the wingspan, which is 11 m / 2 = 5.5 m.Substituting these values into the equation for the acceleration of the wing tip, we get:$$a = \frac{\left(\frac{2\pi (5.5 	ext{ m})}{35 	ext{ s}}ight)^2}{5.5 	ext{ m}} = 0.18 	ext{ m/s}^2$$Therefore, the acceleration of the wing tip is 0.18 m/s^2.

Uniform Circular Motion: an Aircraft Performs a Maneuver Called an "Aileron