Multielectron atoms: What is the wavelength of the K_α line for Mercury?

Question

Quizplus · Accepted Answer

The K_α line is emitted when an electron falls from the L shell to the K shell. The energy of the K_α line is given by the difference in energy between the L and K shells. For Mercury, the energy of the K_α line is 10.2 keV. The wavelength of the K_α line is given by the equation:λ = hc/Ewhere h is Planck's constant, c is the speed of light, and E is the energy of the photon. Substituting the values for h, c, and E into the equation, we get:λ = (6.626 × 10^-34 J s)(3 × 10⁸ m/s)/(10.2 keV) = 1.94 × 10^-11 mTherefore, the wavelength of the K_α line for Mercury is 1.94 × 10^-11 m.

Multielectron Atoms: What Is the Wavelength of the Kα Line

Multielectron Atoms: What Is the Wavelength of the K_α Line