Bohr atom: A hydrogen atom is excited to the n = 10 stated. It then decays to the n = 4 state by emitting a photon which is detected in a photographic plate. What is the frequency of the detected photon? The lowest level energy state of hydrogen is -13.6 eV. (h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19 J) A) 3.46 × 10¹⁴ Hz B) 0.865 × 10¹⁴ Hz C) 1.27 × 10¹⁴ Hz D) 4.05 × 10¹⁴ Hz E) 1.73 × 10¹⁴ Hz

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The Answer of Bohr atom: A hydrogen atom is excited to the n = 10 stated. It then decays to the n = 4 state by emitting a photon which is detected in a photographic plate. What is the frequency of the detected photon? The lowest level energy state of hydrogen is -13.6 eV. (h = 6.626 × 10^-34 J ∙ s, 1 eV = 1.60 × 10^-19 J) A) 3.46 × 10¹⁴ Hz B) 0.865 × 10¹⁴ Hz C) 1.27 × 10¹⁴ Hz D) 4.05 × 10¹⁴ Hz E) 1.73 × 10¹⁴ Hz

Bohr Atom: a Hydrogen Atom Is Excited to the N