Constant acceleration: A ball rolls across a floor with an acceleration of 0.100 m/s² in a direction opposite to its velocity. The ball has a velocity of 4.00 m/s after rolling a distance 6.00 m across the floor. What was the initial speed of the ball? A) 4.15 m/s B) 5.85 m/s C) 4.60 m/s D) 5.21 m/s E) 3.85 m/s

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Quizplus · Accepted Answer

Explanation:The equation of motion for constant acceleration is:v^2 = u^2 + 2aswhere:v is the final velocityu is the initial velocitya is the accelerations is the distance traveledSubstituting the given values into the equation, we get:4.00^2 = u^2 + 2(-0.100)(6.00)16.00 = u^2 - 1.20u^2 = 17.20u = 4.15 m/s

Constant Acceleration: a Ball Rolls Across a Floor with an Acceleration