Thin lenses: A 4.0-cm tall object is placed 50.0 cm from a diverging lens having a focal length of magnitude 25.0 cm. What are the nature and location of the image? The image is

Question

Quizplus · Accepted Answer

Diverging lenses always produce virtual images that are smaller than the object and located on the same side of the lens as the object. The image distance (v) can be found using the lens equation 1/f = 1/v + 1/u, where f is the focal length and u is the object distance. Given f = -25.0 cm (negative for diverging lens) and u = -50.0 cm (negative as the object is on the opposite side of the light's direction), solving the equation gives v = -16.7 cm, indicating the image is 16.7 cm from the lens on the same side as the object. The magnification (m) can be calculated using m = v/u, which gives the height of the image.

Thin Lenses: a 4