Electromagnetic waves: Given that the wavelengths of visible light range from 400 nm to 700 nm, what is the highest frequency of visible light? (c = 3.0 × 10⁸ m/s) A) 3.1 × 10⁸ Hz B) 7.5 × 10¹⁴ Hz C) 2.3 × 10²⁰ Hz D) 4.3 × 10¹⁴ Hz E) 5.0 × 10⁸ Hz

Question

Quizplus · Accepted Answer

We know that the speed of electromagnetic waves (c) is equal to the product of their wavelength (λ) and frequency (f):

c = λf

Rearranging this formula, we get:

f = c/λ

For the highest frequency of visible light, we need to find the shortest wavelength (which corresponds to blue/violet light). Using λ = 400 nm, we get:

f = (3.0 × 10^8 m/s) / (400 × 10^-9 m) = 7.5 × 10^14 Hz

This matches answer choice B.

Electromagnetic Waves: Given That the Wavelengths of Visible Light Range