Field intensity: If a beam of electromagnetic radiation has an intensity of 120 W/m², what is the maximum value of the electric field? (c = 3.0 × 10⁸ m/s, μ₀ = 4π × 10^-7 T ∙ m/A, ε₀ = 8.85 × 10^-12 C²/N ∙ m²) A) 1.5 kV/m B) 1.0 µT C) 1.0 µV/m D) 0.30 kV/m E) 0.0032 V/m

Question

Quizplus · Accepted Answer

The maximum value of the electric field can be found using the formula:
intensity = ½ εcE²
Where ε is the electric constant, c is the speed of light and E is the electric field strength.

Rearranging the formula, we get:
E = √(2I/εc)

Substituting the given values, we get:
E = √(2 x 120 / (8.85 × 10^-12 x 3.0 × 10^8)) = 304.7 V/m ≈ 0.30 kV/m

Therefore, the correct answer is D, 0.30 kV/m.

Field Intensity: If a Beam of Electromagnetic Radiation Has an Intensity