AC generator: You are designing a generator to have a maximum emf of 8.0 V. If the generator coil has 200 turns and a cross-sectional area of 0.030 m², what should be the frequency of the generator in a uniform magnetic field of 0.030 T? A) 7.1 Hz B) 7.5 Hz C) 8.0 Hz D) 22 Hz E) 44 Hz

Question

Quizplus · Accepted Answer

The max emf induced in the coil is given by:
$E_{max} = NAB\omega$
where N is the number of turns, A is the cross-sectional area of the coil, B is the magnetic field strength, and $\omega$ is the angular frequency.

Rearranging, we get:
$\omega = \frac{E_{max}}{NAB}$

Substituting the given values, we get:
$\omega = \frac{8.0	ext{ V}}{(200)(0.030	ext{ m}^2)(0.030	ext{ T})} \approx 7.1	ext{ Hz}$

Therefore, the answer is A) 7.1 Hz.

AC Generator: You Are Designing a Generator to Have a Maximum