Force on currents: A straight wire that is 0.60 m long is carrying a current of 2.0 A. It is placed in a uniform magnetic field of strength 0.30 T. If the wire experiences a force of 0.18 N, what angle does the wire make with respect to the magnetic field?

Question

Quizplus · Accepted Answer

The force on a current-carrying wire in a magnetic field is given by the equation F = BILsinθ, where F is the force, B is the magnetic field strength, I is the current, L is the length of the wire, and θ is the angle between the wire and the magnetic field. Rearranging the equation to solve for θ, we get sinθ = F/BIL. Plugging in the given values, we get sinθ = 0.18 N / (0.30 T x 2.0 A x 0.60 m) = 0.50. Taking the inverse sine of both sides, we get θ = 30°. Therefore, the answer is B.

Force on Currents: a Straight Wire That Is 0