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Potential Energy of a Current Loop: a Round Loop of Diameter

Question 58

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Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J = 0.20 T Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J + 0.40 T Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J . The normal to the loop is parallel to the unit vector Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J = -0.60 Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J - 0.80 Potential energy of a current loop: A round loop of diameter 12 cm, carrying a current of 0.40 A, is placed inside a magnetic field = 0.20 T + 0.40 T . The normal to the loop is parallel to the unit vector = -0.60 - 0.80 . What is the potential energy of the loop? A) -4.5 × 10<sup>-3</sup> J B) +2.0 × 10<sup>-3</sup> J C) -2.0 × 10<sup>-3</sup> J D) -2.3 × 10<sup>-3</sup> J E) +4.5 × 10<sup>-3</sup> J . What is the potential energy of the loop?


A) -4.5 × 10-3 J
B) +2.0 × 10-3 J
C) -2.0 × 10-3 J
D) -2.3 × 10-3 J
E) +4.5 × 10-3 J

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