Kirchhoff's rules: For the circuit shown in the figure, what is the current through resistor R₁? A) 0.071 A B) 0.13 A C) 0.029 A D) 0.016 A

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Using Kirchhoff's rules, we can apply the junction rule at point U1 to find that the current through the branch with RS1 and U1B0 is equal to the current through the branch with R1 and R2. Therefore, we can simplify the circuit to just those two resistors in series. The total resistance of this series circuit is 1730 ohms, and the total voltage is 121 V. Using Ohm's law, we can find the current to be 0.0701 A, which is approximately equal to 0.071 A.

Kirchhoff's Rules: for the Circuit Shown in the Figure, What