Dielectrics: A parallel-plate capacitor with plate separation of 1.0 cm has square plates, each with an area of 6.0 × 10^-2 m². What is the capacitance of this capacitor if a dielectric material with a dielectric constant of 2.4 is placed between the plates, completely filling them? (ε₀ = 8.85 × 10^-12 C²/N ∙ m²)

Question

Quizplus · Accepted Answer

The capacitance of a parallel-plate capacitor with a dielectric is given by C = κε₀A/d. Substituting the given values: C = (2.4)(8.85 × 10⁻¹² C²/N∙m²)(6.0 × 10⁻² m²)/(0.01 m) = 1.3 × 10⁻¹⁰ F.

Dielectrics: a Parallel-Plate Capacitor with Plate Separation of 1