Potential due to point-charges: Two positive point charges +4.00 μC and +2.00 μC are placed at the opposite corners of a rectangle as shown in the figure. (k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C²) (a) What is the potential at point A (relative to infinity) due to these charges?
(b) What is the potential at point B (relative to infinity) due to these charges?

Question

Potential due to point-charges: Two positive point charges +4.00 μC and +2.00 μC are placed at the opposite corners of a rectangle as shown in the figure. (k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C²)

(a) What is the potential at point A (relative to infinity) due to these charges?
(b) What is the potential at point B (relative to infinity) due to these charges?

Quizplus · Accepted Answer

The Answer of Potential due to point-charges: Two positive point charges +4.00 μC and +2.00 μC are placed at the opposite corners of a rectangle as shown in the figure. (k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C²) (a) What is the potential at point A (relative to infinity) due to these charges? (b) What is the potential at point B (relative to infinity) due to these charges?

Potential Due to Point-Charges: Two Positive Point Charges +4