Electric field of a single point-charge: A small glass bead has been charged to 8.0 nC. What is the magnitude of the electric field 2.0 cm from the center of the bead? (k = 1/4πε₀ = 8.99 × 10⁹ N ∙ m²/C²)

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The electric field E due to a point charge is given by E = k * |q| / r². Substituting the given values: E = (8.99 × 10⁹ N∙m²/C²) * (8.0 × 10⁻⁹ C) / (0.02 m)² = 1.8 × 10⁵ N/C.

Electric Field of a Single Point-Charge: a Small Glass Bead