Standing waves on a string: A 2.00-m long piano wire with a mass per unit length of 12.0 g/m is under a tension of 8.00 kN. What is the frequency of the fundamental mode of vibration of this wire?
A) 204 Hz
B) 102 Hz
C) 408 Hz
D) 510 Hz
E) 153 Hz

Question

Quizplus · Accepted Answer

The fundamental frequency of a string is given by:f = (1/2L) * sqrt(T/m)where L is the length of the string, T is the tension, and m is the mass per unit length.Plugging in the given values, we get:f = (1/2 * 2.00 m) * sqrt(8.00 kN / 0.012 kg/m)= 204 HzTherefore, the correct answer is A.

Standing Waves on a String: a 2