Interference: Two identical loudspeakers that are 5.00 m apart and face toward each other are driven in phase by the same oscillator at a frequency of 875 Hz. The speed of sound in the room is 344 m/s. If you start out standing midway between the speakers, find the shortest distance you can walk toward either speaker in order to hear a minimum of sound.
A) 0.0983 m
B) 0.197 m
C) 0.295 m
D) 0.393 m
E) 0.590 m

Question

Quizplus · Accepted Answer

The shortest distance to a minimum is one-quarter of a wavelength. The wavelength is:$$\lambda = v/f = 344	ext{ m/s}/875	ext{ Hz} = 0.393	ext{ m}$$So, the shortest distance is:$$d = \lambda/4 = 0.393	ext{ m}/4 = 0.0983	ext{ m}$$

Interference: Two Identical Loudspeakers That Are 5