Viscosity: Glycerin, with a viscosity of 1.50 N ∙ s/m², is flowing with an average speed of 1.20 m/s through a tube that has a radius of 5.00 mm and is 25.0 cm long. What is the drop in pressure between the ends of the tube? A) 144 kPa B) 45.8 kPa C) 72.0 kPa D) 76.3 kPa E) 129 kPa

Question

Quizplus · Accepted Answer

The drop in pressure can be calculated using Poiseuille's law: ΔP = 8μLv / πr^4, where ΔP is the pressure drop, μ is the viscosity, L is the length of the tube, v is the average speed, and r is the radius of the tube. Substituting the given values (μ = 1.50 N∙s/m^2, L = 0.25 m, v = 1.20 m/s, r = 0.005 m), we find ΔP = 8 * 1.50 * 0.25 * 1.20 / (π * (0.005)^4) = 144 kPa.

Viscosity: Glycerin, with a Viscosity of 1