Mass on a spring: An object that weighs 2.450 N is attached to an ideal massless spring and undergoes simple harmonic oscillations with a period of 0.640 s. What is the spring constant of the spring?
A) 2.45 N/m
B) 12.1 N/m
C) 24.1 N/m
D) 0.102 N/m
E) 0.610 N/m

Question

Quizplus · Accepted Answer

We can begin by using the formula for the period of a mass-spring system:

T = 2π√(m/k)

Where T is the period, m is the mass, and k is the spring constant. We can rearrange this formula to solve for k:

k = (2π/m)² x m / T²

Plugging in the given values, we get:

k = (2π/2.450)² x 2.450 / 0.640²

k = 24.1 N/m

Therefore, the spring constant of the spring is 24.1 N/m, which corresponds to choice C.

Mass on a Spring: an Object That Weighs 2