Damped harmonic motion: A 5.0-kg block is attached to an ideal massless spring whose spring constant is 125 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a position at x = +0.687 m and is released from rest. The block then executes lightly damped oscillation along the x-axis, and the damping force is proportional to the velocity. When the block first returns to x = 0.00 m, its x component of velocity is -2.0 m/s and its x component of acceleration is +5.6 m/s2.
(a) What is the magnitude of the acceleration of the block upon release at x = +0.687 m.
(b) Find the damping constant b.

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The Answer of Damped harmonic motion: A 5.0-kg block is attached to an ideal massless spring whose spring constant is 125 N/m. The block is pulled from its equilibrium position at x = 0.00 m to a position at x = +0.687 m and is released from rest. The block then executes lightly damped oscillation along the x-axis, and the damping force is proportional to the velocity. When the block first returns to x = 0.00 m, its x component of velocity is -2.0 m/s and its x component of acceleration is +5.6 m/s2.
(a) What is the magnitude of the acceleration of the block upon release at x = +0.687 m.
(b) Find the damping constant b.

Damped Harmonic Motion: a 5