A randomized block design ANOVA has five treatments and four blocks. The computed test statistic (value of F) is 6.25. With a 0.05 significance level, the conclusion will be to accept the null hypothesis.

Question

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To draw a conclusion, one needs to compare the computed test statistic with the critical value of F. The critical value of F for a 0.05 significance level with four and 20 degrees of freedom (four blocks and five treatments) is 2.866. Since 6.25 is greater than 2.866, the null hypothesis is rejected in favor of the alternative hypothesis. Therefore, the answer is False, not True.

A Randomized Block Design ANOVA Has Five Treatments and Four