A random variable x is normally distributed with a mean of 150 and a variance of 36. Given that x = 120, its corresponding z-score is 5.0.

Question

Quizplus · Accepted Answer

This statement is false. The given z-score of 5.0 suggests that x = 120 is unlikely under a normal distribution with mean 150 and variance 36. The actual z-score for x = 120 can be calculated as:

z = (120 - 150) / 6 = -5

Thus, the given z-score in the statement is incorrect.

A Random Variable X Is Normally Distributed with a Mean