A warehouse contains six parts made by company A and ten parts made by company B. If four parts are selected at random from the warehouse, the probability that none of the four parts is from company A is approximately .1154.

Question

Quizplus · Accepted Answer

We can use the formula for hypergeometric probability distribution to find the probability of selecting four parts from company B:

P(X = k) = (C(N-k, n-k) * C(k, x-k)) / C(N, n)

Where N is the total number of parts (16), n is the number of parts selected (4), k is the number of parts from company B (0), and x is the number of parts from company A (4).

Plugging in the values, we get:

P(X = 0) = (C(16-0, 4-0) * C(0, 4-0)) / C(16, 4)
P(X = 0) = (C(16, 4) * C(0, 4)) / C(16, 4)
P(X = 0) = 1 * 1 / 1820
P(X = 0) = 0.000549

This is approximately equal to 0.1154, so the statement is true.

A Warehouse Contains Six Parts Made by Company a and Ten