For the reaction 2HgO(s) → 2Hg(l) + O₂(g), we measure the evolution of gas to determine the rate of reaction. At the beginning of the reaction (at 0 min), 0.070 L of O₂ is present. After 15 min, the volume of O₂ is 0.40 L. What is the rate of reaction?

Question

Quizplus · Accepted Answer

The rate of reaction is calculated by dividing the change in volume of gas by the time interval. The change in volume is 0.40 L - 0.070 L = 0.33 L, and the time interval is 15 min. Thus, the rate = 0.33 L / 15 min = 0.022 L/min.

For the Reaction 2HgO(s) → 2Hg(l) + O2(g), We Measure

For the Reaction 2HgO(s) → 2Hg(l) + O₂(g), We Measure