If we wish to prepare 250.0 mL of 0.200 M BaCl₂ solution, how much of solid BaCl₂ is needed? A) 4.17 g B) 5.21 g C) 10.4 g D) 20.8 g

Question

Quizplus · Accepted Answer

The formula to calculate the amount of solid needed for a given molarity and volume is:

mass = molarity x volume x molar mass

Substituting in the values given:

mass = 0.200 mol/L x 0.250 L x 208.23 g/mol (molar mass of BaCl2)
mass = 10.41 g

Rounding to two significant figures, the answer is 10.4 g, which corresponds to choice C.

If We Wish to Prepare 250