Assuming that the volumes are additive, what volume of water must be added to 35.0 mL of 12.0 M HCl to make a 3.00 M solution?
A) 70.0 mL
B) 87.5 mL
C) 105 mL
D) 140 mL

Question

Quizplus · Accepted Answer

M1V1 = M2V2
(12.0 M)(35.0 mL) = (3.00 M)(V2)
V2 = (12.0 M)(35.0 mL) / (3.00 M)
V2 = 140 mL
Thus, we need to add (140 mL - 35.0 mL) = 105 mL of water to make a 3.00 M solution. Therefore, the answer is choice C.

Assuming That the Volumes Are Additive, What Volume of Water