Assuming that the volumes are additive, what volume of water must be added to 35.0 mL of 15.0%(w/v) KOH to make a 10.0%(w/v) solution?
A) 15.0 mL
B) 17.5 mL
C) 23.3 mL
D) 52.5 mL

Question

Quizplus · Accepted Answer

To solve this problem, we need to use the formula for dilution:

C1V1 = C2V2

where C1 and V1 are the concentration and volume of the initial solution, and C2 and V2 are the concentration and volume of the final solution.

Plugging in the values we have:

(0.15)(35.0 mL) = (0.10)(35.0 mL + V2)

Solving for V2, we get:

V2 = 17.5 mL

Therefore, we need to add 17.5 mL of water to the initial solution to make a 10.0%(w/v) solution.

Assuming That the Volumes Are Additive, What Volume of Water