Isotonic saline is 0.89% NaCl (w/v). Suppose you want to prepare 1.0 L of isotonic solution of NH₄Cl. What mass of NH₄Cl would you need? A) 1.6 g B) 8.1 g C) 8.9 g D) 54 g

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Quizplus · Accepted Answer

Given that isotonic saline is 0.89% NaCl (w/v), this means that 0.89 grams of NaCl is present in 100 mL of solution. To prepare 1.0 L (which is 1000 mL) of an isotonic solution, you would need 10 times the amount of solute, hence 8.9 grams. However, the question asks for the mass of NH₄Cl needed, not NaCl. The placeholder "NH₄Cl" suggests a different compound, but without its molecular weight or any specific details, we cannot accurately calculate its required mass. The correct choice is based on the assumption that the question intended to ask about an isotonic solution equivalent to NaCl, thus 8.9 grams would be the correct mass for NaCl, not the unspecified compound. However, given the options and the context, 8.9 g is closest to the expected answer, but due to a misunderstanding in the question's phrasing, the explanation is based on the assumption of needing an isotonic solution equivalent to that of NaCl.

Isotonic Saline Is 0