If 2 mol of NO gas occupies 10.0 L at 295 K, what is the pressure of the gas in atmospheres?
A) 0.206 atm
B) 2.42 atm
C) 4.84 atm
D) 9.33 atm

Name: If 2 mol of NO gas occupies 10.0 L at 295 K, what is the pressure of the gas in atmospheres? A) 0.206 atm B) 2.42 atm C) 4.84 atm D) 9.33 atm
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Question

Quizplus · Accepted Answer

Using the ideal gas law, PV = nRT, where n = 2 mol, R = 0.0821 L·atm/mol·K, T = 295 K, and V = 10.0 L, the pressure P is calculated as P = (nRT)/V = (2 mol * 0.0821 L·atm/mol·K * 295 K) / 10.0 L = 4.84 atm.

If 2 Mol of NO Gas Occupies 10