The combustion of one mole of propane, C₃H₈, releases 531 kcal of heat. How much heat is released by the combustion of 4.40 g of propane?

Question

Quizplus · Accepted Answer

To find the heat released by the combustion of 4.40 g of propane, first calculate the moles of propane in 4.40 g. The molar mass of propane (C3H8) is approximately 44.1 g/mol. Thus, 4.40 g of propane is 4.40 g / 44.1 g/mol = 0.1 mol. Since the combustion of one mole releases 531 kcal, the combustion of 0.1 mol releases 531 kcal × 0.1 = 53.1 kcal.

The Combustion of One Mole of Propane, C3H8, Releases 531

The Combustion of One Mole of Propane, C₃H₈, Releases 531