Aluminum has a density of 2.70 g/cm³. What volume is occupied by a block of aluminum that weighs 4.32 kg? A) 0.000625 cm³ B) 0.625 cm³ C) 1.60 cm³ D) 1.60 L

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Quizplus · Accepted Answer

To find the volume occupied by the aluminum block, we use the formula: volume = mass / density. First, convert 4.32 kg to grams (4.32 kg * 1000 g/kg = 4320 g) because the density is given in g/cm^3. Then, divide the mass by the density (4320 g / 2.70 g/cm^3 = 1600 cm^3). Since 1 cm^3 = 1 mL and 1000 mL = 1 L, 1600 cm^3 = 1.60 L.

Aluminum Has a Density of 2