Sodium-21 will emit positrons, each having an energy of 4.0 × 10-13 J. What is this energy in MeV? (1 MeV = 1.602 × 10-13 J)
A) 4.0 × 10-7 MeV
B) 2.5 MeV
C) 40 MeV
D) 2.5 × 106 MeV
E) 2.5 × 10-6 MeV
Correct Answer:
Verified
Q47: What element is the stable end-product of
Q64: The dose unit of ionizing radiation is
Q70: What causes the radiation damage to matter
Q72: Which statement is false?
A) Fission occurs among
Q73: A 30.0-kg child receives 2.65 × 107
Q76: Which type of radiation is the least
Q77: Calcium-39 undergoes positron decay. Each positron carries
Q78: A 55-kg person exposed to thorium-234 receives
Q79: Which of the following is an advantage
Q80: Which type of radiation is the most
Unlock this Answer For Free Now!
View this answer and more for free by performing one of the following actions
Scan the QR code to install the App and get 2 free unlocks
Unlock quizzes for free by uploading documents