If 50.0 mL of 1.2 × 10^-3^MPb(NO₃)₂ are added to 50.0 mL of 2.0 × 10^-4^M Na₂S, what takes place?

Question

Quizplus · Accepted Answer

When solutions of Pb(NO3)2 and Na2S are mixed, a precipitate of PbS (lead sulfide) forms due to the insolubility of PbS in water. This is a result of a double displacement reaction where the cation of one reactant (Pb2+) combines with the anion of the other reactant (S2-) to form an insoluble compound, PbS.

If 500 ML of 1