At elevated temperatures, hydrogen iodide may decompose to form hydrogen gas and iodine gas, as follows. 2HI(g) H₂(g) + I₂(g)
In a particular experiment, the concentrations at equilibrium were measured to be [HI] = 0.85 mol/L, [I₂] = 0.60 mol/L, and [H₂] = 0.27 mol/L. What is K_c for the above reaction?

Question

At elevated temperatures, hydrogen iodide may decompose to form hydrogen gas and iodine gas, as follows. 2HI(g)

H₂(g) + I₂(g)
In a particular experiment, the concentrations at equilibrium were measured to be [HI] = 0.85 mol/L, [I₂] = 0.60 mol/L, and [H₂] = 0.27 mol/L. What is K_c for the above reaction?

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The Answer of At elevated temperatures, hydrogen iodide may decompose to form hydrogen gas and iodine gas, as follows. 2HI(g) H₂(g) + I₂(g) In a particular experiment, the concentrations at equilibrium were measured to be [HI] = 0.85 mol/L, [I₂] = 0.60 mol/L, and [H₂] = 0.27 mol/L. What is K_c for the above reaction?

At Elevated Temperatures, Hydrogen Iodide May Decompose to Form Hydrogen