Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C₁₇H₃₅COOH (C₁₇H₃₅COOH) ₂; ΔH°_rxn = -172 kJ/mol
The equilibrium constant for this reaction at 28°C is 2.9 × 10³. Estimate the equilibrium constant at 38°C. (R = 8.314 J/K• mol)

Question

Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C₁₇H₃₅COOH

Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C<sub>17</sub>H<sub>35</sub>COOH (C<sub>17</sub>H<sub>35</sub>COOH) <sub>2</sub>; ΔH°<sub>rxn</sub> = -172 kJ/mol The equilibrium constant for this reaction at 28°C is 2.9 × 10<sup>3</sup>. Estimate the equilibrium constant at 38°C. (R = 8.314 J/K• mol) A) 4.7 × 10<sup>5</sup> B) 2.6 × 10<sup>4</sup> C) 1.9 × 10<sup>3</sup> D) 3.2 × 10<sup>2</sup> E) 18

(C₁₇H₃₅COOH) ₂; ΔH°_rxn = -172 kJ/mol
The equilibrium constant for this reaction at 28°C is 2.9 × 10³. Estimate the equilibrium constant at 38°C. (R = 8.314 J/K• mol)

Quizplus · Accepted Answer

The Answer of Stearic acid, nature's most common fatty acid, dimerizes when dissolved in hexane: 2C₁₇H₃₅COOH (C₁₇H₃₅COOH)₂; ΔH°_rxn = -172 kJ/mol The equilibrium constant for this reaction at 28°C is 2.9 × 10³. Estimate the equilibrium constant at 38°C. (R = 8.314 J/K• mol)

Stearic Acid, Nature's Most Common Fatty Acid, Dimerizes When Dissolved