Suppose 75.0 g of PCl₅(g) is introduced into an evacuated 3.00-L vessel and allowed to reach equilibrium at 250ºC. PCl₅(g) PCl₃(g) + Cl₂(g)
If K_P = 1.80 for this reaction, what is the total pressure inside the vessel at equilibrium? (R = 0.0821 atm • L/mol • K)

Question

Suppose 75.0 g of PCl₅(g) is introduced into an evacuated 3.00-L vessel and allowed to reach equilibrium at 250ºC. PCl₅(g) Suppose 75.0 g of PCl5(g) is introduced into an evacuated 3.00-L vessel and allowed to reach equilibrium at 250ºC. PCl5(g) PCl3(g) + Cl2(g) If KP = 1.80 for this reaction, what is the total pressure inside the vessel at equilibrium? (R = 0.0821 atm • L/mol • K) A) 2.88 atm B) 2.28 atm C) 4.54 atm D) 7.43 atm E) 9.69 atm

Suppose 75.0 g of PCl<sub>5</sub>(g) is introduced into an evacuated 3.00-L vessel and allowed to reach equilibrium at 250ºC. PCl<sub>5</sub>(g) PCl<sub>3</sub>(g) + Cl<sub>2</sub>(g) If K<sub>P</sub> = 1.80 for this reaction, what is the total pressure inside the vessel at equilibrium? (R = 0.0821 atm • L/mol • K) A) 2.88 atm B) 2.28 atm C) 4.54 atm D) 7.43 atm E) 9.69 atm

PCl₃(g) + Cl₂(g)
If K_P = 1.80 for this reaction, what is the total pressure inside the vessel at equilibrium? (R = 0.0821 atm • L/mol • K)

Quizplus · Accepted Answer

The Answer of Suppose 75.0 g of PCl₅(g) is introduced into an evacuated 3.00-L vessel and allowed to reach equilibrium at 250ºC. PCl₅(g) PCl₃(g) + Cl₂(g) If K_P = 1.80 for this reaction, what is the total pressure inside the vessel at equilibrium? (R = 0.0821 atm • L/mol • K)