The rate constant for the reaction 3A → 4B is 6.00 × 10^-3 L• mol^-1• min^-1. How long will it take the concentration of A to drop from 0.75 M to 0.25 M?

Question

Quizplus · Accepted Answer

The reaction is a second-order reaction with respect to A, so the integrated rate law is 1/[A] = kt + 1/[A]₀. Plugging in the values: 1/0.25 = (6.00 × 10⁻³)t + 1/0.75, solving for t gives 440 min.

The Rate Constant for the Reaction 3A → 4B Is