The rate law for the reaction 3A → C is rate = 4.36 × 10^-2 L• mol^-1• h^-1[A]². What is the half-life for the reaction if the initial concentration of A is 0.250 M?

Question

Quizplus · Accepted Answer

The reaction is second order, so the half-life is given by t₁/₂ = 1 / (k[A]₀). Substituting the given values, t₁/₂ = 1 / (4.36 × 10⁻² L•mol⁻¹•h⁻¹ × 0.250 mol/L) = 91.7 h.

The Rate Law for the Reaction 3A → C Is