What mass of KClO₃ must be decomposed to produce 126 L of oxygen gas at 133°C and 0.880 atm? (The other reaction product is solid KCl.) (R = 0.08206 L • atm/K • mol)

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Quizplus · Accepted Answer

Using the ideal gas law, calculate moles of O2: PV = nRT. Convert 133°C to Kelvin (406 K). n = (0.880 atm * 126 L) / (0.08206 L•atm/K•mol * 406 K) = 3.33 mol O2. The balanced equation is 2 KClO3 → 2 KCl + 3 O2, so 2 mol KClO3 produce 3 mol O2. Thus, 3.33 mol O2 requires 2.22 mol KClO3. Molar mass of KClO3 is 122.55 g/mol, so mass = 2.22 mol * 122.55 g/mol = 272 g.

What Mass of KClO3 Must Be Decomposed to Produce 126

What Mass of KClO₃ Must Be Decomposed to Produce 126