The combustion of pentane produces heat according to the following thermochemical equation. C₅H₁₂(l) + 8O₂(g) → 5CO₂(g) + 6H₂O(l) ΔH°_rxn= -3510 kJ/mol
How many grams of CO₂is produced per 2.50 × 10³ kJ of heat released?

Question

Quizplus · Accepted Answer

The reaction releases 3510 kJ per mole of pentane combusted, producing 5 moles of CO₂. For 2500 kJ, the moles of CO₂ produced is (2500 kJ / 3510 kJ/mol) * 5 mol. Converting this to grams using the molar mass of CO₂ (44.01 g/mol) gives approximately 157 g.

The Combustion of Pentane Produces Heat According to the Following