As a research assistant, you are asked to prepare a 3.00 liter solution of magnesium sulfate at 45.0 micromoles per liter. How many moles of magnesium sulfate are required to make this solution?

Question

Quizplus · Accepted Answer

To find the moles of magnesium sulfate required, multiply the concentration (45.0 micromoles per liter) by the volume of the solution (3.00 liters). Since 1 micromole = 10^-6 moles, 45.0 micromoles = 45.0 × 10^-6 moles. Therefore, (45.0 × 10^-6 moles/L) × 3.00 L = 0.000135 moles.

As a Research Assistant, You Are Asked to Prepare a 3.00