50.0 grams of acetic acid are required for an experiment. What volume, in milliliters, of a 1.105 g/cm³acetic acid solution must be measured for the experiment?

Question

Quizplus · Accepted Answer

We can use the equation:

mass = volume x density

Rearranging, we get:

volume = mass/density

The mass of acetic acid required is 50.0 grams.

The density of the 1.105 g/cm³ acetic acid solution is given in the question.

Substituting the values, we get:

volume = 50.0 g / 1.105 g/cm³ = 45.2 cm³

However, the question asks for the volume in milliliters (mL), so we need to convert cm³ to mL:

volume = 45.2 cm³ x (1 mL / 1 cm³) = 45.2 mL

Therefore, the answer is B, 45.2 mL.

500 Grams of Acetic Acid Are Required for an Experiment