The oxidation of myristyl-CoA (C-14:0) yields
A) 7 acetyl-CoA + 7 FADH2 + 7 NADH + 7 H+.
B) 6 acetyl-CoA + 7 FADH2 + 7 NADH + 7 H+.
C) 7 acetyl-CoA + 6 FADH2 + 6 NADH + 6 H+.
D) 7 acetyl-CoA + 7 FAD + 7 NAD+.
E) 14 acetyl-CoA + 12 FADH2 + 12 NADH + 12 H+.
Correct Answer:
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