If a galaxy has an apparent recession velocity of 8000 km/sec and the Hubble constant is approximately 70 km/sec/Mpc, what is the distance to this galaxy?

Question

Quizplus · Accepted Answer

The distance to the galaxy can be calculated using Hubble's Law, which is $v = H_0 \times d$, where $v$ is the recession velocity, $H_0$ is the Hubble constant, and $d$ is the distance to the galaxy. Rearranging for $d$, we get $d = \frac{v}{H_0}$. Substituting $v = 8000$ km/sec and $H_0 = 70$ km/sec/Mpc, we get $d = \frac{8000}{70} = 114$ Mpc.

If a Galaxy Has an Apparent Recession Velocity of 8000