-If the orbital velocity of the lower-mass star in an eclipsing binary is 97 km/sec and it is completely eclipsed by the more massive star for 2 hours, what is the approximate diameter of the more massive star?

Question

Quizplus · Accepted Answer

The diameter of the more massive star can be calculated by multiplying the orbital velocity of the lower-mass star (97 km/sec) by the time it is eclipsed (2 hours or 7200 seconds). This gives 97 km/sec * 7200 sec = 699,840 km, which is approximately 700,000 km.

-If the Orbital Velocity of the Lower-Mass Star in an Eclipsing