An object released from rest on another planet requires 1 s to fall a distance of 6 m. What is the acceleration in meters per second squared due to gravity on this planet?
A)3
B)6
C)12
D)15
E)none of the above

Question

Quizplus · Accepted Answer

The formula for distance fallen under constant acceleration is $d = \frac{1}{2}gt^2$. Plugging in the values, $6 = \frac{1}{2}g(1^2)$, we solve for $g$ to find $g = 12 \, \text{m/s}^2$.

An Object Released from Rest on Another Planet Requires 1