The pH = -log[H⁺] for a solution. The pOH = -log[OH^-] for a solution. The pH and pOH are related, and their sum is equal to 14 (pH + pOH = 14). If the concentration of a dilute solution of potassium hydroxide is 0.001 M, what is the pH of that solution?

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Given the concentration of potassium hydroxide (KOH) is 0.001 M, we first calculate the pOH using the formula pOH = -log[OH-]. Since KOH is a strong base, it dissociates completely in water, releasing OH- ions with a concentration of 0.001 M. Thus, pOH = -log(0.001) = 3. Using the relationship pH + pOH = 14, we find pH = 14 - pOH = 14 - 3 = 11.

The PH = -Log[H+] for a Solution

The PH = -Log[H⁺] for a Solution