Determine the equilibrium concentration of cadmium when the carbonate concentration is 5.4 × 10^-7 M. The K_sp for CdCO₃ is 1.0 × 10^-12.

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Quizplus · Accepted Answer

The solubility product (Ksp) for CdCO3 is given as 1.0 × 10^-12. The reaction can be represented as CdCO3(s) ⇌ Cd^2+(aq) + CO3^2-(aq). Since the concentration of CO3^2- is given as 5.4 × 10^-7 M, we can set up the expression for Ksp as [Cd^2+][CO3^2-] = 1.0 × 10^-12. Solving for [Cd^2+] gives [Cd^2+] = (1.0 × 10^-12) / (5.4 × 10^-7) = 1.9 × 10^-6 M.

Determine the Equilibrium Concentration of Cadmium When the Carbonate Concentration