Determine the equilibrium concentration of bromide when the lead concentration is 2.8 × 10^-3 M. The K_sp of PbBr₂ is 6.60 × 10^-6.

Name: Determine the equilibrium concentration of bromide when the lead concentration is 2.8 × 10 -3 M. The K sp of PbBr 2 is 6.60 × 10 -6 .
Brand: Quizplus
Rating: 4.9 (54 reviews)

Question

Quizplus · Accepted Answer

The solubility product expression for PbBr2 is Ksp = [Pb^2+][Br^-]^2. Given [Pb^2+] = 2.8 × 10^-3 M, solve for [Br^-]: 6.60 × 10^-6 = (2.8 × 10^-3)[Br^-]^2. Solving gives [Br^-] ≈ 0.049 M.

Determine the Equilibrium Concentration of Bromide When the Lead Concentration