A gas initially occupies 4.50 L at 23°C and 1.50 atm. Calculate its volume after the temperature is increased to 160°C and the pressure is decreased to 0.50 atm.

Question

Quizplus · Accepted Answer

To solve this problem, we use the combined gas law, which is $P_1V_1/T_1 = P_2V_2/T_2$, where $P$ is pressure, $V$ is volume, and $T$ is temperature in Kelvin. First, convert temperatures to Kelvin: $T_1 = 23°C + 273 = 296K$ and $T_2 = 160°C + 273 = 433K$. Then, rearrange the formula to solve for $V_2$: $V_2 = V_1 \times (P_1/P_2) \times (T_2/T_1)$. Substituting the given values gives $V_2 = 4.50L \times (1.50 atm / 0.50 atm) \times (433K / 296K) = 19.7L$.

A Gas Initially Occupies 4