Let's say that you are testing an individual's ability to discriminate tones. When the test stimulus is set at 200 Hz, the person reports a JND at 210 Hz. If I change the test frequency, the value of a JND becomes 50 Hz. What is the new test frequency?

Question

Quizplus · Accepted Answer

The Just Noticeable Difference (JND) is proportional to the initial stimulus intensity according to Weber's Law. Given that the JND for 200 Hz is 10 Hz (210 - 200), and the JND changes to 50 Hz for the new test frequency, we can set up a proportion: 10/200 = 50/x. Solving for x gives us 1000 Hz, indicating that the new test frequency is 1000 Hz.

Let's Say That You Are Testing an Individual's Ability to Discriminate